Given that 0.8 is one root of the equation, X3 -&n - Exam Yatra

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ESE 2018 Prelims Paper I
Engineering aptitude
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Engineering aptitude

11

M: +2.00/-0.66

Given that 0.8 is one root of the equation, X³ - 0.6X² - 1.8X + 1.344 = 0. The other roots of this equation will be

[ESE 2018 Prelims Paper I]

A 1.1 and -1.4

B -1.2 and 1.4

C 1.2 and -1.4

D -1.1 and 1.4

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