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Number 136 is added to 5B7 and the sum obtained is 7A3, where A and B are integers. It is given that 7A3 is exactly divisible by 3. The only possible value of B is

[Paper II (CSAT) Analysis 2019]
A
B
C
D

EXPLANATION

Answer is (d). It is given 136 + 5B7 = 7A3. Add the unit’s numbers...
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